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Molarity

20 mL of 0....

Question

$20 m L$ of $0.2 M A l_{2} (S O_{4})_{3}$ is mixed with $20$ mL of $6.6 M$ $B a C l_{2}$ , the concentration of $C l^{-}$ ion in solution is?

0.2 M

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6.6 M

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0.02 M

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0.06 M

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Solution

The correct option is B $6.6 M$
$20 m L$ of $0.2 M$ $A l_{2} (S O_{4})_{3}$ is mixed with $20 m L$ of $6.6 M$ $B a C l_{2}$

Concentration of $C l^{-} = \frac{T o t a l a m o u n t o f c h l o r i d e}{T o t a l v o l u m e}$

Total amount of chloride ion in solution $= 2 \times 20 m l \times 6.6 m m o l / m l = 264 m m o l$

Total volume $= 20 + 20 = 40 m L$

$∴$ Concentration of $C l^{-}$ ion $= \frac{264}{40} = 6.6 M$ .

Hence, the correct option is $B .$

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