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Standard XII

Chemistry

Concentration Terms - An Introduction (w/w etc)

20 ml of a ga...

Question

$20$ ml of a gaseous hydrocarbon required $400$ ml of air for complete combustion. The air contains $20$ % by volume of oxygen. The volume of gaseous mixture after explosion and cooling was found to be $380$ ml. Volume of $C O_{2}$ is:

40 ml

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60 ml

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80 ml

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100 ml

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Solution

The correct option is A 60 ml
According to given,
Volume of $O_{2} = 400 \times 0.20 = 80 m l$
So Volume of residual $N_{2} = (400 - 80) = 320 m l$
so Volume of $C O_{2} = (380 - 320) = 60 m l$

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20 ml of a gaseous hydrocarbon required 400 ml of air for complete combustion. The air contains 20% by volume of oxygen. The volume of gaseous mixture after explosion and cooling was found to be 380 ml. Volume of CO2 is:

The correct option is A 60 mlAccording to given,Volume of O2=400×0.20=80mlSo Volume of residual N2=(400−80)=320mlso Volume of CO2=(380−320)=60ml

$20$ ml of a gaseous hydrocarbon required $400$ ml of air for complete combustion. The air contains $20$ % by volume of oxygen. The volume of gaseous mixture after explosion and cooling was found to be $380$ ml. Volume of $C O_{2}$ is:

The correct option is A 60 ml
According to given,
Volume of $O_{2} = 400 \times 0.20 = 80 m l$
So Volume of residual $N_{2} = (400 - 80) = 320 m l$
so Volume of $C O_{2} = (380 - 320) = 60 m l$