$20 m l$ of a mixture of $C_{2} H_{2}$ and $C O$ was exploded with $30 m l$ of oxygen. The gases after reaction has a volume of $34 m l$ . On treatment with $K O H, 8 m l$ of oxygen remained. Calculate volume of $C_{2} H_{2}$ in the mixture.

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Solution

Let $V_{0} f C_{2} H_{2}$ be a
then $V$ ef $C O_{2} = (20 - a)$

$C_{2} H_{2} + \frac{5}{2} O_{2} \to 2 C O_{2} + H_{2} O$
$a$ $2 a$
$C O + \frac{1}{2} O_{2} \to C O_{2}$
$(20 - a)$ $(20 - a)$
gas formed is $C O_{2}$ with volume
$8 + 2 a + 20 - a = 28 + a$
$∴ a = 34 - 28 = a^{6} m l$
volume of $C_{2} H_{2} = 6 m l$

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