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Oxides of Nitrogen

20 mL of a sa...

Question

20 mL of a sample of $H_{2} O_{2}$ gives 400 mL oxygen measured at NTP. The sample should be labeled as:

5 V H_{2} O_{2}

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dil.

H_{2} O_{2}

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anhy.

H_{2} O_{2}

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20 V H_{2} O_{2}

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Solution

The correct option is D $20 V H_{2} O_{2}$
20 mL of a sample of $H_{2} O_{2}$ gives 400 mL $o x y g e n$ measured at NTP.
1 mL of the sample of $H_{2} O_{2}$ will give $\frac{400}{20} = 20$ mL $o x y g e n$ measured at NTP.
The sample should be labeled as $20 V H_{2} O_{2}$ .

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