You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Limiting Reagent or Reactant

20 ml of meth...

Question

20 ml of methane was exploded with $80$ ml of $O_{2}$ and cooled to room temperature, the final volume of gaseous mixture is:

30 m l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 m l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60 m l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100 m l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $60 m l$
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

$1$ vol $2$ vol $1$ vol
$20$ mL $40 m L$ $20 m L$

volume of $O_{2}$ left unused $= 80 - 40 = 40 m L$

$40 m L$ on cooling water vapour changes into liquid volume of gases after cooling

$= 40 m L + 20 m L C O_{2}$

$= 60 m L$

So, the correct ans is $C$

Suggest Corrections

Similar questions

When 20ml of methane and 20ml of oxygen are exploded together and the reaction mixture is cooled to laboratory temperature. The resulting volume of the mixture

Q. 20 ml of mixture of CO and

H_{2}

were mixed with excess of

O_{2}

and exploded and cooled . There was a volume contraction of 18 ml . All volume measurements corresponds to room temperature

(27^{0} C)

and one atmosphere pressure . Determine the volume ratio

V_{1} : V_{2}

of CO and

H_{2}

in the original mixture.

50

mL of a mixture of

C O

and

C H_{4}

was exploded with

85

mL of

O_{2}

. The volume of

C O_{2}

produced was

50

mL. Calculate the percentage composition of the gaseous mixture:

Q. A mixture of

100 mL

C O, C O_{2}

and

O_{2}

was sparked. When the resulting gaseous mixture was passed through

K O H

solution, the contraction in volume was found to be

80 mL

. The composition of the initial mixture may be (in the same order):

24 m l

of water gas containing only hydrogen and carbon monoxide in equal proportions by volume, are exploded with

80 m l

of air,

20

by volume of which is oxygen. If all gaseous volumes are measured at room temperature and pressure, calculate the composition by volume of the resulting gaseous mixture.

Join BYJU'S Learning Program

20 ml of methane was exploded with 80 ml of O2 and cooled to room temperature, the final volume of gaseous mixture is:

The correct option is D 60 mlCH4+2O2→CO2+2H2O1vol 2vol 1vol20mL 40mL 20mLvolume of O2 left unused =80−40=40mL40mL on cooling water vapour changes into liquid volume of gases after cooling =40mL+20mLCO2=60mLSo, the correct ans is C

20 ml of methane was exploded with $80$ ml of $O_{2}$ and cooled to room temperature, the final volume of gaseous mixture is: