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Question

20 ml of mixture of CO and C2H4 was exploded with 50 mL of O2. The volume after explosion was 45 mL of shaking with NaOH solution only 15 mL O2 was left behind , what were the volume of CO and C2H4 in mixture?

A
CO=5mL, C2H2=15 mL
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B
CO=10mL, C2H2=10 mL
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C
CO=8mL, C2H2=12 mL
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D
CO=15mL, C2H2=5 mL
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Solution

The correct option is B CO=10mL, C2H2=10 mL
Solution:-
Let the mixture contain xmL of C2H4 and ymL of CO.

C2H4x+3O22CO22x+2H2O

COy+12O2CO2y

NaOH absorbs the CO2 produced in the reaction.

Total amount of CO2 produced =2x+y=(4515)
2x+y=30.....(1)

Given that:-

x+y=20.....(2)
From eqn(1)&(2), we have

20+y=30
y=10mL

Substituting the value of y in eqn(2), we have
x+10=20
x=10mL
Hence the volume of CO and C2H4 in the mixture is 10mL and 10mL respectively.

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