MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Concentration Terms - An Introduction (w/w etc)

20 mL of x ...

Question

$20$ mL of $x M$ $H C l$ neutralizes completely $10$ mL of $0.1 M$ $N a H C O_{3}$ solution and a further $5$ mL of $0.2 M$ $N a_{2} C O_{3}$ solution to methyl orange end point. The value of $x$ is:

A

0.167 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

0.133 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

0.15 M

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

0.2 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $0.15 M$
$20$ mL of $x M$ $H C l = 10$ mL of $0.1 M$ $N a H C O_{3} + 5$ mL of $0.2 M N a_{2} C O_{3}$
(Methyl orange indicated $100 %$ reaction of $N a H C O_{3}$ and $N a_{2} C O_{3}$ )
$0.2 M$ $N a_{2} C O_{3} = 0.4 M N a_{2} C O_{3}$
$20 \times x - 10 \times 0.1 = 5 \times 0.1 \times 2 \Rightarrow x = 0.15$

Suggest Corrections

thumbs-up

0

Similar questions

20

x

H C l

neutralises completely

10

0.1 M

N a H C O_{3}

5

0.2 M N a_{2} C O_{3}

solution to methyl orange end-point. The value of

x

Q. A solution contains

N a_{2} C O_{3}

N a H C O_{3}

10 mL

of this solution required

2.5 mL

0.1 M H_{2} S O_{4}

for neutralization using phenolphthalein as an indicator. Methyl orange is then added when a further

2.5 mL

0.2 M H_{2} S O_{4}

was required. The amount of

N a_{2} C O_{3}

N a H C O_{3}

respectively, in 1 litre of solution is:

[⊝ O H]

of a solution is

2.8 \times 10^{- x} M

100

0.1 M

M g C l_{2}

100

0.2 M

NaOH. The value of

x

K_{s p} M g (O H)_{2} = 1.2 \times 10^{- 11}

Q. A solution contains

N a_{2} C O_{3}

N a H C O_{3}, 10 m L

of this solution required

2.5 m L

0.1 M H_{2} S O_{4}

for neutralisation using phenolphthalein indicator. Methyl orange is added after first end point, further titration required

2.5 m L

0.2 M H_{2} S O_{4}

. The amount of

N a_{2} C O_{3}

N a H C O_{3}

1

litre of the solution is:

Q. For a given mixture of

N a H C O_{3}

N a_{2} C O_{3}

, volume of a given

H C l

x

mL with phenolphthalein indicator and further

y

mL required with methyl orange indicator. Hence, volume of

H C l

for complete reaction of

N a H C O_{3}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Reactions in Solutions

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Concentration Terms - An Introduction (w/w etc)

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon