CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Source and Listener Moving in Different Lines

20. particle ...

Question

20. particle performs simple harmonic motion with an amplitude of 4 cm. At the mean position the velocity of the particle is 10cm/s. The distance of the particle from the mean position when its speed becomes 5cm/s is (1)\sqrt{}3cm (2)\sqrt{}5cm (3)2\sqrt{}3cm (4)2\sqrt{}5cm

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

A particle executes simple harmonic motion with an amplitude of 4 cm. At the

mean position the velocity of the particle is 10 cm/s. The distance of the

particle from the mean position when its speed becomes 5 cm/s is

[EAMCET (Med.) 2000]

Q. A particle executes simple harmonic motion with an amplitude of

4 c m .

At the mean position the velocity of the particle is

10 c m / s

. The distance of the particle from the mean position when its speed becomes

5 c m / s

Q. A particle executes simple harmonic motion along a straight line with mean position at

x = 0

20 s

and amplitude of

5 c m

. The shortest time taken by the particle to go from

x = 4

x = - 3

Q. A particle executes simple harmonic motion with an amplitude of

5 cm

. When the particle is at

4 cm

from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is

Q. A particle performing simple harmonic motion has maximum velocity

8 c m / s

and has acceleration

16 c m / s^{2}

at a distance of

4 c m

from the mean position. Calculate the time period and amplitude.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Doppler's Effect

PHYSICS

Watch in App

explore_more_icon

Explore more

Source and Listener Moving in Different Lines

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon