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Question

20 Nm torque is applied to a flywheel that rotates about a fixed axis and has moment of inertia of 25 kgm2. If the flywheel is initially at rest, what is its angular velocity after it has turned through 10 revolutions?

A
5 rad/s
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B
15 rad/s
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C
20 rad/s
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D
10 rad/s
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Solution

The correct option is D 10 rad/s
Given torque, τ=20 Nm
Moment of inertia of flywheel, I=25 kgm2.
The flywheel turns through 10 revolutions, which is 20π radians.
The work done by the torque,
W=τ(θ2θ1)=ΔKErot
W=τ(θ2θ1)=12Iω2212Iω21
Here, (θ2θ1)=20π given
ω1=0 (Flywheel initially at rest).

τ(θ2θ1)=12Iω2212Iω21
20×20π=12×25×ω2212×25×0
ω2=10 rad/s
The angular velocity of flywheel after 10 revolutions is 10 rad/s.

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