20. The minimum value of the quadratic equation x 2 -4x+7, for real values of x is:

(a) 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b) 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(d) 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D (d) 3
Ans: (d)
Sol: X 2 -4x+7 can be written as (xx)-4x+4+3

(x-2)(x-2) +3. Since (x-2) 2 can take only positive value or zero, the minimum value of (x-2)*(x-2) +3 is 3.

Suggest Corrections

Similar questions

x^{2} - 4 x + k = 0

f (x) = x^{2} + 4 x + 17

x

k

x^{2} - 4 x + k = 0

x^{2} - 4 x - {log}_{3} a = 0

a

The roots of a quadratic equation $x^{2} - 4 x - a = 0$ are real. Then what is the least value of $a$ ?

Join BYJU'S Learning Program