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Conduction Law

20. The speci...

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20. The specific heat of silver is 0.0565cal/g^° C. Assuming no loss of heat to the surrounding or system, calculate the final temperature when 100g of silver at 40^° C is immersed in 60g of water at 10^° C.

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A mass of 50 g of a certain metal at $150^{\circ} C$ is immersed in 100 g of water at $11^{\circ} C$ . The final temperature is $20^{\circ} C$ . Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2 J $g^{- 1} K^{- 1}$ .

10 g

- 20^{\circ} C

20 g

20^{\circ} C

. Assuming that no heat is lost to the surrounding, find the final temperature of the mixture.
[Take, specific heat capacity of ice

C_{i} = 2100 {J kg}^{- 1}^{\circ} C^{- 1}

, specific heat capacity of water

C_{w} = 4200 {J kg}^{- 1}^{\circ} C^{- 1}

& Latent heat of fusion of ice

L = 3 .36 \times 10^{5} {J kg}^{- 1}

]

Q. 1 kg of water at

20^{\circ} C

is, mixed with 800 g of water at

80^{\circ} C

. Assuming that no heat is lost to the surroundings. Calculate the final temperature of the mixture.

50 g

of a certain metal at

150^{\circ} C

100 g

11^{\circ} C

. The final temperature is

20^{\circ} C

. Find the specific heat capacity of the metal.
Specific heat capacity of water is

4.2 J g^{- 1} K^{- 1}

Q. Ice in a freezer is at

- 7^{\circ} C . 100 g

of this ice is mixed with

200 g

15^{\circ} C

. Take the freezing temperature of water to be

0^{\circ} C

, the specific heat of ice equal to

2.2 J / g^{\circ} C

, specific heat of water equal to

4.2 J / g^{\circ} C

, and the latent heat of ice equal to

335 J / g

. Assuming no loss of heat to the environment, the mass of ice in the final mixture is closest to

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