$20$ times the area of the plot in sq. km. is

Open in App

Solution

Scaling factor = $\frac{L e n g t h o f m o d e l}{L e n g t h o f b u i l d i n g}$
$\frac{1}{250000} = \frac{A B}{L e n g t h_{A B}}$
$L e n g t h_{A B} = 250000 \times 3$
$L e n g t h_{A B} = 750000$
$L e n g t h_{A B} = 7.5$ km
$\frac{1}{250000} = \frac{B C}{L e n g t h_{B C}}$
$L e n g t h_{B C} = 250000 \times 4$
$L e n g t h_{B C} = 1000000$
$L e n g t h_{B C} = 10$ km
Area of plot = $\frac{1}{2} \times L e n g t h_{A B} \times L e n g t h_{B C}$ (Area of triangle = $\frac{1}{2} b a s e \times h e i g h t$ )
Area of plot = $\frac{1}{2} \times (7.5) \times 10$
Area of plot = $37.5$ $k m^{2}$

Suggest Corrections

Similar questions

Q. A 1 sq. km circular field is divided into 3 equal plots. If each plot is shared among 2 farmers, the area allotted to each farmer is sq. km

State true or false:

On a map drawn to a scale of 1: 25,0000; a triangular plot of land has the following measurements AB=3 cm, BC=4 cm, and angle ABC=

90^{\circ} .

The area of the plot in sq. km is 37.5 sq. km.

Q. On a map drawn to a scale of

1 : 25000

, a rectangular plot of land,

A B C D

has the following measurements

A B = 12 c m

and

B G = 16 c m

. Calculate:
(i) the distance of a diagonal of the plot in km.
(ii) the area of the plot in sq. km.

Q. The population of an area X is 2000. The area of the place is 2 square kilometer. What is the population density of area X?

On a map, drawn to a scale of 1 : 2,50,000; a triangular plot of land has the following measurements : AB = 3 cm, BC = 4 cm and angle ABC = $90^{\circ}$ . Calculate : (i) the actual lengths of AB and BC in km. (ii) the area of the plot in sq. km.

Join BYJU'S Learning Program

20 times the area of the plot in sq. km. is

$20$ times the area of the plot in sq. km. is