20 tuning forks are arranged in series in such a way that each fork gives 3 beats/s with the previous one. If the last fork is one octave lowet of first fork then frequency of tenth fork is

Open in App

Solution

Suggest Corrections

Similar questions

Q. A set of 24 tuning forks are so arranged in series that each gives 4 beats per second with the previous one and the last sounds the octave of the first. Then, the frequency of the fork is :

Q. A set of 12 tuning forks is arranged in the increasing order of frequencies. Each tuning fork produces ‘y’ beats per second with previous one. The last tuning fork is an octave of the first. The fifth tuning fork has frequency 90 Hz. Find ‘y’. Hence find the frequency of the last fork.

Q. A set of 56 tuning forks are so arranged in series that each fork gives 4 beats per second with the previous one. The frequency of the last fork Is 3 times that of the first. The frequency of the first fork is

$25$ tuning forks are arranged in series in the order of decreasing frequency. Any two successive forks produce $3$ beats/s. If the frequency of the first tuning fork is the octave of the last fork, then the frequency of the $21$ st fork is :

Q. A set of

48

tuning forks is arranged in a series of descending frequencies such that each fork gives

4

beats per second with preceding one. The frequency of first fork is

1.5

times the frequency of the last fork, find the frequency of the first and

42^{n d}

tuning fork.

Join BYJU'S Learning Program