20. Why cos (-theta)is equal to cos( theta)

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\tan θ = \frac{a}{b}, then \frac{a \sin θ + b \cos θ}{a \sin θ - b \cos θ}

\frac{a^{2} + b^{2}}{a^{2} - b^{2}}

\frac{a^{2} - b^{2}}{a^{2} + b^{2}}

\frac{a + b}{a - b}

\frac{a - b}{a + b}

cos θ + cos 2 θ + cos 3 θ + \dots . + cos {(n - 1) θ} + cos n θ

cos 4 θ - cos 6 θ

4 cos 6 θ cos 4 θ cos 2 θ

If $c o s 2 θ = a$ then $\frac{c o s 3 θ}{c o s θ}$ equals to

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