$200 c . c .$ of a gas measured at S.T.P. has a mass of $0.268 g$ . Molecular weight of the gas is:

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Solution

The correct option is D
30

$200 c c \to 0.268 g m$

$22400 c c \to x g$

$x = \frac{0.268 \times 22400}{200} = 30$

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