Question

$200c{m}^3$ of a solution of a dibasic acid contains $1.512g$ of the acid and the normality of the solution is $\mathrm{0.12.}$ Calculate the equivalent mass.

Answer 1

Mass of the acid in one $d{m}^3$ of the solution $=1.512\times 5=7.56g.$

Equivalent mass $=\frac{massperd{m}^3}{normality}=\frac{7.56}{0.12}=63$