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Ways of Representing the Concentration of a Solution

200 g of Ca...

Question

200 g of $C a C O_{3}$ are taken in a 4 L container at a certain temperature. $K_{c}$ for the dissociation of $C a C O_{3}$ at this temperature is found to be $1 / 4 m o l e L^{- 1}$ . Then, the concentration of $C a O (s)$ in mole/litre is

1/2

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1/4

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0.02

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Solution

The correct option is C 1/4
The reaction is

$C a C O_{3} (s) \to C a O (s) + C O_{2} (g)$

$K_{c} = \frac{[C a O] [C O_{2}]}{[C a C O_{3}]}$

But $C a O$ and $C a C O_{3}$ are in solid state so concentration of both two can be taken as unity .

$∴ K_{c} = [C O_{2}]$

But $K_{c} = \frac{1}{4}$

$∴ [C O_{2}] = \frac{1}{4}$

As in the reaction , first step reaction we see that 1 mole of $C a C O_{3}$ produces 1 mole of $C a O$ and $C O_{2}$ .

Therefore ,

$[C a O] = [C O_{2}]$

$∴ [C a O] = \frac{1}{4}$

Hence , option B is correct .

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