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Thermal Energy

200 g of hot ...

Question

200 g of hot water at 80°C is added to 300 g of cold water at 10°C. Calculate the final temperature of the mixture of water. Consider the heat taken by the container to be negligible. The specific heat capacity of water is 4200 J kg^-1 °C^-1

A

38^oC

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B

40^oC

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C

20^oC

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D

50^oC

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Solution

The correct option is A
38^oC

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Similar questions

200 g

of hot water at

80^{\circ} C

300 g

of cold water at

10^{\circ} C

. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water =

44200 J k g^{- 1} K^{- 1}

.

200 g

of hot water at

80^{o} C

300 g

of cold water at

10^{o} C

. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water

= 4200 J k g^{- 1} K^{- 1}

10 g

- 20^{\circ} C

20 g

20^{\circ} C

. Assuming that no heat is lost to the surrounding, find the temperature of the mixture.
[Take, specific heat capacity of ice

C_{i} = 2100 {J kg}^{- 1}^{\circ} C^{- 1}

, specific heat capacity of water

C_{w} = 4200 {J kg}^{- 1}^{\circ} C^{- 1}

& Latent heat of fusion of ice

L = 3 .36 \times 10^{5} {J kg}^{- 1}

]

Q. A 5g piece of ice at

- 20^{\circ}

C is put into 10g of water at

30^{\circ}

C. Assuming that heat is enchanged only between the ice and the water, find the final temperature of the mixture. Specific heat capacity of ice

= 2100 J k g^{- 1}^{\circ} C^{- 1}

. Specific heat capacity of water

= 4200 J k g^{- 1}^{\circ} C^{- 1}

and latent heat of fusion of ice

3.36 \times 10^{5} J k g^{- 1}

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A calorimeter contains 5 kg of water at 30°C. A metal of mass 4 kg at 100^oC is added to the calorimeter. The final temperature is recorded as 70^oC. Find the specific heat capacity of the metal. Given: Specific heat capacity of water 4200 J kg^–1°C^–1.

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