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Standard X

Physics

Effect of High Latent Heat of Fusion of Ice

200 g of ice ...

Question

$200 g$ of ice at $0^{\circ} C$ converts into water at $0^{\circ} C$ in 1 minute when heat is supplied to it at a constant rate. In how much time $200 g$ of water at $0^{\circ} C$ will change to $20^{\circ} C$ ? Take specific latent heat of ice = $336 J g^{- 1}$

5 s

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10 s

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15 s

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30 s

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Solution

The correct option is D $15 s$
Heat supplied to melt ice $Q = 200 \times 336 = 67200 J$
this heat is supplied in $t = 60 s e c$
rate of heat supply= $\frac{67200}{60} = 1120 J / s$
heat required to raise temperature by $11^{o} C$
$Q_{1} = 200 \times 4.2 \times 20 = 16800 J$
times required = $\frac{16800}{1120} = 15 s$

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200

g of ice at

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250 g

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How much heat energy is released when 5.0 g of water at $20^{o} C$ changes into ice at $0^{o} C$ ? Take specific heat capacity of water = 4.2 J $g^{-} 1 K^{- 1}$ , specific latent heat of fusion of ice = 336 J $g^{- 1}$ .

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200 g of ice at 0∘C converts into water at 0∘C in 1 minute when heat is supplied to it at a constant rate. In how much time 200 g of water at 0∘C will change to 20∘C ? Take specific latent heat of ice = 336Jg−1

The correct option is D 15 sHeat supplied to melt ice Q=200×336=67200Jthis heat is supplied in t=60 secrate of heat supply=6720060=1120J/s heat required to raise temperature by 11oC Q1=200×4.2×20=16800Jtimes required =168001120=15 s

$200 g$ of ice at $0^{\circ} C$ converts into water at $0^{\circ} C$ in 1 minute when heat is supplied to it at a constant rate. In how much time $200 g$ of water at $0^{\circ} C$ will change to $20^{\circ} C$ ? Take specific latent heat of ice = $336 J g^{- 1}$