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Standard XII

Physics

Area and Volume Expansion

200 gm of a s...

Question

200 gm of a solid ball at $20^{0} C$ is dropped in an equal amount of water at $80^{0} C$ . The resulting temperature is $60^{0} C$ . This means that specific heat of solid is

one-fourth of water

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one-half of water

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twice of water

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four times of water

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Solution

The correct option is B
one-half of water

Heat gained by the ball = heat lost by water
200 $\times$ c $\times$ (60-20)=200 (1)(80-60)
2c = 1 $\Rightarrow c = \frac{1}{2}$

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200 gm of a solid ball at 200C is dropped in an equal amount of water at 800C. The resulting temperature is 600C. This means that specific heat of solid is

The correct option is B one-half of water Heat gained by the ball = heat lost by water 200 × c × (60-20)=200 (1)(80-60) 2c = 1 ⇒c=12

200 gm of a solid ball at $20^{0} C$ is dropped in an equal amount of water at $80^{0} C$ . The resulting temperature is $60^{0} C$ . This means that specific heat of solid is

The correct option is B
one-half of water

Heat gained by the ball = heat lost by water
200 $\times$ c $\times$ (60-20)=200 (1)(80-60)
2c = 1 $\Rightarrow c = \frac{1}{2}$