Question

200 gm of a solid ball at ${20}^{0}C$ is dropped in an equal amount of water at ${80}^{0}C$. The resulting temperature is ${60}^{0}C$. This means that specific heat of solid is

• A. one-fourth of water
• B. one-half of water
• C. twice of water
• D. four times of water

Answer 1

The correct option is B

one-half of water

Heat gained by the ball = heat lost by water
200 $\times$ c $\times$ (60-20)=200 (1)(80-60)
2c = 1 $\Rightarrow c=\frac{1}{2}$