Question

200 grams of marble chips are dropped into 100g of hydrochloric acid. How much chips will remain undissolved? What weight of anhydrous calcium chloride and what weight of ${\text{CO}}_{\text{2}}$ gas could be obtain from it? CaCO${}_3\to$ CaO + ${\text{CO}}_{\text{2}}$

Answer 1

Moles of $CaC{O}_3=\frac{200}{100}=2$ $moles$

Moles of $HCl=\frac{100}{36.5}=2.74$ $moles$

$CaC{O}_3+2HCl⟶CaC{l}_2+C{O}_2+H_{2}O$

$2$ $2.74$

$0.63$ $1.37$ $1.37$ $1.37$

$\to HCl$ is limiting.

$\to 0.63$ $moles$ of $CaC{O}_3$ i.e., $63$ $gms$ remains undissolved.

$\to 1.37$ $moles$ of $CaC{l}_2$ are formed, Mass $=111\times 1.37=152.67$ $gm$

$\to 1.37$ $moles$ of $C{O}_2$ are formed, Mass $=44\times 1.37=60.28$ $gm$