Question

200 mL of 0.1 M $H_{2}S{O}_4$ is added to 300 mL of 0.1 M $NaOH$ solution. Find the normality of the ions in excess ($H^{+}$ or $O{H}^{-}$) in the resultant solution.

• A. 0.25 N
• B. 0.30 N
• C. 0.02 N
• D. 0.05 N

Answer 1

The correct option is C 0.02 N

Milliequivalents of $NaOH$ $=300\times 0.1\times 1=30$
Milliequivalents of $H_{2}S{O}_4=200\times 2\times 0.1=40$
Since, the acid is present in excess, the solution is acidic.
Hence, milliequivalents of excess $H^{+}$ = 40 – 30 = 10
Normality of $H^{+}=\frac{10}{500}=0.02$ N