Question

200 mL of a strong acid solution of pH = 2.0 is mixed with 800 mL of another acid solution of pH = 3.0. The pH of resultant solution is

• A. 2.10
• B. 2.31
• C. 2.55
• D. 2.89

Answer 1

The correct option is C

2.55

[$H+$] from 200 ml pH 2.0 solution = .01x(200)/1000
[$H^{+}$] from 800 ml pH 3.0 solution = .001x(800)/1000
Adding both [H⁺] = 2.8 x 10^-3

Hence pH = 2.55