Question

$200V$ AC source is fed to series LCR circuit having $X_L=50\Omega ,X_C=50\Omega$ and $R=25\Omega$. Potential drop across the inductor is :

• A. $100V$
• B. $200V$
• C. $400V$
• D. $10V$

Answer 1

The correct option is C $400V$

Here $V_{rms}=200V,X_L=50\Omega ,X_C=50\Omega ,R=25\Omega$

Impedance of the circuit,
$Z=\sqrt{R^2+(X_L-X_C{)}^2}=\sqrt{{25}^2+(50-50{)}^2}=25\Omega$

Current in the circuit , $I_{rms}=\frac{V_{rms}}{Z}=\frac{200V}{25\Omega }=8A$

Voltage drop across the inductor is

$V_L=I_{rms}{X}_L=8A\times 50\Omega =400V$