wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

200V AC source is fed to series LCR circuit having XL=50Ω,XC=50Ω and R=25Ω. Potential drop across the inductor is :

A
100V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
200V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
400V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 400V
Here Vrms=200V,XL=50Ω,XC=50Ω,R=25Ω

Impedance of the circuit,
Z=R2+(XLXC)2=252+(5050)2=25Ω

Current in the circuit , Irms=VrmsZ=200V25Ω=8A

Voltage drop across the inductor is

VL=IrmsXL=8A×50Ω=400V

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Series RLC
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon