Question

${}^{200}X{\to }^{110}A{+}^{90}B+Energy$
If the binding energy per nucleon for $X,A$and$B$ are 7.4 MeV, 8.2 MeV and 8.2 MeV respectively, the minimum energy required to bring in this reaction will be :

• A. 90 MeV
• B. 100 MeV
• C. 120 MeV
• D. 160 MeV

Answer 1

The correct option is D 160 MeV

Accordint to given data,
Energy required $=110\times 8.2+90\times 8.2-200\times 7.4=(200\times 8.2)-200\times 7.4$$=160MeV$