Question

$2000calories$ of heat is supplied to $200g$ of water. Find the rise in temperature. Specific heat capacity of water $(1cal/gC)$

Answer 1

Step 1: Given data

Heat supplied (Q) = $2000calories$

Mass of water (m) = $200g$

Specific heat capacity of water (c) = $(1cal/gC)$

Let rise in temperature = $∆t$

Step 2: Calculation of change in temperature

$Q=mc∆t$

$2000=200x1x∆t$

$∆t=\frac{2000}{200}={10}^{°}C$

Hence, ${10}^{°}C$ is the correct answer.