Question

$21\frac{1}{3},16,12,9,?$

• A. $7$
• B. $6$
• C. $6.75$
• D. $5$

Answer 1

The correct option is C $6.75$

Given numbers are in GP $\Rightarrow r=\frac{3}{4}$

Where $r$ is the common ratio of G.P.
$\therefore$Required number is $=9\times \frac{3}{4}=6.75$