$21 m^{2} \div 7 m$

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Solution

$21 m^{2} \div 7 m$
$= \frac{21 m^{2}}{7 m} = 3 m$ .

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Similar questions

Q. Solve:

21 m^{2} \div 7 m

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21 m^{2} + 7 m = 0

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(a)

21 m^{2} \div 7 m

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If the area of a rectangle of length = 3 m and width = 7 m is $21 m^{2},$ then what is the volume of a rectangular block having length = 3 m, width = 7 m and height = 1 m?

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21m2÷7m

21m2÷7m=21m27m=3m.

$21 m^{2} \div 7 m$

$21 m^{2} \div 7 m$
$= \frac{21 m^{2}}{7 m} = 3 m$ .