Question

21.wavelength of light used in an optical instrument are wavelength 1=40000⁰A and wavelength 2=5000 ⁰A, then the ratio of their respective resolving powers (corresponding to wavelength 1 and wavelength 2) is -----------

Answer 1

$$\begin{gathered} ResolvingPower,R=\frac{1.21\lambda }{D} \\ \frac{R_1}{R_2}=\frac{{\lambda }_1}{{\lambda }_2}=\frac{40000}{5000}=8:1 \end{gathered}$$