Question

${}_{84}^{210}Po\to {}_{82}^{206}Pb+{}_2^{4}He$

In this reaction predict the position of group of Po when lead is in the IV A group:

• A. II A
• B. IV B
• C. VI B
• D. VI A

Answer 1

The correct option is D VI A

Lead with atomic number $82$ is in group $IVA$.
$Po$ with atomic number $84$ is in group $VIA$.