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Molality

22.22 gram of...

Question

22.22 gram of urea was absolute in 300 gram of water. Calculate the No.of mole of urea and morality of the urea 80. (Given -molar mass of urea = 60 gram $m o l^{- 1}$ )

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Solution

Number of moles = $\frac{m a s s}{m o l a r m a s s}$
= $\frac{22.22}{60}$
= $0.37 m o l e s$
$M o l a l i t y = \frac{m o l e s}{k g (H_{2} O)} = \frac{0.37}{0.3}$
= $1.23 m$

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