22.4 litres of a gas weighs 70 g at S.T.P. Calculate the weight of the gas if it occupies a volume of 20 litres at 27 degree celsius and 700 Hg of pressure.

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Solution

Dear student,
we know that
PV= nRT
here,
R= 0.082
P=700/760= 0.921 atm
T = 273 + 27=300
as PV= nRT
So,0.921 * 20= n0.082300
therefore n= .748 moles
1 mole contains 70g
therefore, weight of .748 moles is 0.748*70/1
= 52.414
Regards,

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22.4 litres of a gas weighs 70 g at S.T.P. Calculate the weight of the gas if it occupies a volume of 20 litres at 27 degree celsius and 700 Hg of pressure.

Dear student, we know that PV= nRT here, R= 0.082 P=700/760= 0.921 atm T = 273 + 27=300 as PV= nRT So,0.921 * 20= n*0.082*300 therefore n= .748 moles 1 mole contains 70g therefore, weight of .748 moles is 0.748*70/1 = 52.414 Regards,

Dear student,
we know that
PV= nRT
here,
R= 0.082
P=700/760= 0.921 atm
T = 273 + 27=300
as PV= nRT
So,0.921 * 20= n0.082300
therefore n= .748 moles
1 mole contains 70g
therefore, weight of .748 moles is 0.748*70/1
= 52.414
Regards,