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Question

22.4 litres of a gas weighs 70g at S.T.P. Calculate the weight of the gas if it occupies a volume of20 litres at 27℃ and 700 mm Hg of pressure

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Solution

According to ideal gas equationpV= nRTpV=WMRTp =700 mm of mercury (convert this to atm because the R value is in atm 760 mm og Hg =1 atm so 700 mm of Hg = 700760)V= 20 LT = 27 0C = 27 + 273 = 300 KR = 0.0821 L atmM = molecular mass = 70 g (since 1 mole of any gas occupies 22.4 L)W= ?W= MpVRT = 70 × 700760 × 200.0821 × 300 = 52.35 g

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