Question

$22.4$ litres of $H_{2}S$ and $22.4$ litres of $S{O}_2$ both at STP are mixed together. The amount of sulphur precipitated as a result of chemical reaction is:

• A. $16g$
• B. $23g$
• C. $48g$
• D. $96g$

Answer 1

Answer: (C)

$48g$

$2H_{2}S+S{O}_2\to 2H_{2}O+3S$

Moles of $H_{2}S=1$

Moles of $Sformed=\frac{3}{2}\times 1=1.5$

Weight of $S=1.5\times 32=48gm$