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Standard XII
Chemistry
Examples of Ionic Compounds
22. The heat ...
Question
22. The heat of formation (N2O5,g) in KJ/mol on the bases of the following data is 2NO(g)+O2(g)---->2NO2(g) H= -114kJ/mol 4NO2(g)+O2(g)--->2N2O5(g) H= -102.6KJ/mol Heat of formation (NO,g)= 90.2 kJ/mol 1)15.1 2)30.2 3)-36.2 4 none of these
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Similar questions
Q.
Compute the heat of formation of liquid methyl alcohol in kilojoules per mole using the following data.
The heat of vaporisation of liquid methyl alcohol =
38
k
J
/
m
o
l
.
The heats of formation of gaseous atoms from the elements is their standard states:
H
,
218
k
J
/
m
o
l
;
C
,
713
k
J
/
m
o
l
;
O
,
249
k
J
/
m
o
l
.
Average bond energies:
C
−
H
=
415
k
J
/
m
o
l
;
C
−
O
=
365
k
J
/
m
o
l
;
O
−
H
=
463
k
J
/
m
o
l
.
Q.
Compute the heat of formation of liquid methyl alcohol (in kJ mol
−
1
) using the following data. The heat of vaporisation of liquid methyl alcohol is 38 kJ mol
−
1
.
The heat of formation of gaseous atoms from the elements in their standard states:
H
=
218 kJ mol
−
1
.,
C
=
715
kJ mol
−
1
. ,
O
=
249
kJ mol
−
1
.
Average bond energies:
C
−
H
=
415
kJ mol
−
1
.
C
−
O
=
356
kJ mol
−
1
.
O
−
H
=
463
kJ mol
−
1
.
Q.
What is the heat of formation of liquid methyl alcohol in
k
J
m
o
l
−
1
,
use the following data.
Heat of vaporization of liquid methyl alcohol =
38
k
J
m
o
l
−
1
.
Heat of formation of gaseous atoms from the elements in their standard states:
H
=
218
k
J
m
o
l
−
1
,
C
=
715
k
J
m
o
l
−
1
,
O
=
249
k
J
m
o
l
−
1
Average bond energies :
C
−
H
=
415
k
J
m
o
l
−
1
C
−
O
=
356
k
J
m
o
l
−
1
O
−
H
=
463
k
J
m
o
l
−
1
Q.
Compute the heat of formation of liquid methyl alcohol in kilojoules per mole using the following data.
The heat of vaporisation of liquid methyl alcohol =
38
k
J
/
m
o
l
.
The heats of formation of gaseous atoms from the elements in their standard states:
H
,
218
k
J
/
m
o
l
;
C
,
715
k
J
/
m
o
l
;
O
,
249
k
J
/
m
o
l
.
Average bond energies:
C
−
H
=
415
k
J
/
m
o
l
;
C
−
O
=
365
k
J
/
m
o
l
;
O
−
H
=
463
k
J
/
m
o
l
.
Q.
Given the following:
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
394
k
J
/
m
o
l
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
l
)
;
Δ
H
=
−
568
k
J
/
m
o
l
C
2
H
5
O
H
(
l
)
+
3
O
2
(
g
)
→
2
C
O
2
(
g
)
+
3
H
2
O
(
l
)
;
Δ
H
=
−
1058
k
J
/
m
o
l
Using the given data, the heat of formation of ethanol is:
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