Question

$2200$ ${\text{cm}}^3$ of brass is to be drawn into cylindrical wire $0.25$ cm in diameter. What will be the length of the wire?

Answer 1

radius of the wire $=\frac{1}{8}cm$
If $l$ be length of the wire, then
Volume of the wire $=\pi \times \frac{1}{8}\times \frac{1}{8}\times lc{m}^3$
Thus,$\frac{22}{7}\times \frac{1}{8}\times \frac{1}{8}\times l=2200$
or $l=44800cm$ or $448m$