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Latent Heat

22320 cal of ...

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22320 cal of heat is supplied to 100g of ice at 0^° C. If thelatent heat of fusion of ice is 80 cal gand latent heat ofvaporization of water is 540 cal g-1the final amount ofwater thus obtained and its temperature respectively are

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22320

cal of heat is supplied to

100 g

0^{\circ} C

. If the latent heat of fusion of ice is

80 c a l g^{- 1}

and latent heat of vaporization of water is

540 c a l g^{- 1}

, the final amount of water thus obtained and its temperature respectively are

Q. The amount of heat required to raise the temperature of

75 g

0^{o} C

10^{o} C

[latent heat of fusion of ice is

80 c a l / g

, specific heat of water is

1 c a l / g^{o} C

2 g

100^{\circ} C

6 g

0^{\circ} C

. If the latent heat of steam and ice are

540 cal/g

80 cal/g

respectively and specific heat capacity of water is

1 cal / g^{\circ} C

, then the final temperature of the mixture is

Q. How much heat is required to change

10 g

0^{o} C

100^{o} C

? Latent heat of fusion and vaporization for

H_{2} O

80 c a l / g

540 c a l / g

respectively. Specific heat of water is

1 c a l / g

10 g

0^{o} C

100 g

50^{o} C

in a calorimeter. The final temperature of the mixture is [Specific heat of water

= 1 c a l g^{- 1}^{o} C^{- 1}

, latent heat of fusion of ice

= 80 c a l g^{- 1}]

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