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Standard VII
Biology
Food Storage and Preservation
225 ml of 0.1...
Question
225 ml of 0.1 M acetic acid is titrated with 0.1 MNaOH solution. The pH of the solution atequivalence point will be (log 5 = 0.7 and pKa ofCH,COOH 4.76)(1) 8.73(2) 9.73(4) 8.212(3) 7.13
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Q.
When 10 mL of 0.1 M acetic acid
(
p
K
a
=
5.0
)
is titrated against 10 mL of 0.1 M ammonia solution
(
p
K
b
=
5.0
)
the equivalence point occurs at pH of:
Q.
When
10
m
L
of
0.1
M
acetic acid (
p
K
a
=
5.0
) is titrated against
10
m
L
of
0.1
M
ammonia solution
(
p
K
b
=
5.0
)
, the equivalence point occurs at pH:
Q.
When 50 mL of 0.1 M NaOH is added to 50 mL of 0.1 M
C
H
3
C
O
O
H
solution, the pH will be:
(use :
(
p
K
a
)
a
c
e
t
i
c
a
c
i
d
=
5
,
l
o
g
2
=
0.3
,
l
o
g
3
=
0.5
,
l
o
g
5
=
0.7
)
Q.
When 50 mL of 0.1 M NaOH is added to 50 mL of 0.1 M
C
H
3
C
O
O
H
solution, the pH will be:
(use :
(
p
K
a
)
a
c
e
t
i
c
a
c
i
d
=
5
,
l
o
g
2
=
0.3
,
l
o
g
3
=
0.5
,
l
o
g
5
=
0.7
)
Q.
The pH at the equivalence point in the titration of
25
ml of
0.10
M formic acid with a
0.1
M
N
a
O
H
solution ( given that
p
K
a
of formic acid
=
3.74
) is:
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