You visited us 61 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Solving Linear Differential Equations of First Order

226 Ra disint...

Question

$^{226} R a$ disintegrates at such a rate that after $3160$ yrs only one-fourth of its original amount remains. Half-life of $^{226} R a$ will be:

790

years

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3160

years

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1580

years

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6230

years

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1580$ years
After 1 half life, amount becomes half and after two half life amount becomes one-fourth.
Therefore, $2 t_{h a l f} = 3160$
$= t_{h a l f} = 1580 y r s$

Suggest Corrections

Similar questions

Q. If in

3160

years, a radioactive substance becomes one-fourth of the original amount, find its half-life period.

Q. Uranium ores contain one raidum

- 226

atom for every

2.8 \times 10^{6}

uranium-238 atoms. Calculate the half-life of

_{92} U^{238}

, given that the half-life of

_{88} R a^{226}

1600

years

(_{88} R a^{226}

is a decay product of

_{92} U^{238})

Q. Uranium ores contain one radium

- 226

atoms for every

2.8 \times 10^{6}

uranium

- 238

atoms. Calculate the half - life of

_{92}^{238} U

, given that the half - life of

_{88}^{226} R a

is 1600 years. (

_{88}^{226} R a

is a decay product of

_{92}^{238} U

)

Q. Uranium ores contain one radium

- 226

atoms for every

2.8 \times 10^{6}

uranium

- 238

atoms. Calculate the half - life of

_{92}^{238} U

, given that the half - life of

_{88}^{226} R a

is 1600 years. (

_{88}^{226} R a

is a decay product of

_{92}^{238} U

)

Q. The half-life of

^{226}

Ra is 1602 year. The activity of 0.1g of RaCl

_{2}

assuming all the Ra atoms are

^{226}

Ra and mass of Cl atom 35.5g/mol is

Join BYJU'S Learning Program

226Ra disintegrates at such a rate that after 3160 yrs only one-fourth of its original amount remains. Half-life of 226Ra will be:

The correct option is C 1580 yearsAfter 1 half life, amount becomes half and after two half life amount becomes one-fourth. Therefore, 2thalf=3160 =thalf=1580 yrs

$^{226} R a$ disintegrates at such a rate that after $3160$ yrs only one-fourth of its original amount remains. Half-life of $^{226} R a$ will be:

The correct option is C $1580$ years
After 1 half life, amount becomes half and after two half life amount becomes one-fourth.
Therefore, $2 t_{h a l f} = 3160$
$= t_{h a l f} = 1580 y r s$