$2 {\sqrt{2 a}}^{3} + 3 {\sqrt{3 b}}^{3} + c^{3} - 3 \sqrt{6} a b c$

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Solution

The given expression to be factorized is

This can be written in the form

Recall the formula

Using the above formula, we have

We cannot further factorize the expression.

So, the required factorization is of is .

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Similar questions

2 \sqrt{2} a^{3} + 3 \sqrt{3} b^{3} + c^{3} - 3 \sqrt{6} a b c

2 \sqrt{2} a^{3} + 16 \sqrt{2} b^{3} + c^{3} - 12 a b c

2 \sqrt{2} a^{3} + 16 \sqrt{2} b^{3} + c^{3} - 12 a b c

(a^{2} b^{2} c^{3} - a^{2} b^{2} c^{3} + a^{2} b^{2} c^{3}) \div a^{2} b^{2} c^{3}

{(a + b + c)}^{3} - a^{3} - b^{3} - c^{3} = 3 (a + b) (b + c) (c + a)

{(a + b + c)}^{3} - a^{3} - b^{3} - c^{3} = [{(a + b + c)}^{3} - a^{3}] - [b^{3} + c^{3}]

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