Question

${}_{11}^{23}Na$ changes to ${}_{12}^{24}Mg$ by bombardment of ${}_o^{1}n$ and successive emission of $\beta$-particle.

• A. True
• B. False

Answer 1

The correct option is A True

Reaction:

${}_{11}^{23}Na{+}_o^{1}n⟶{}_{12}^{24}Mg+{}_{-1}^{0}e$ ( $\beta$-particle).

So, the given statement is correct.