Question

# 23. edr23. xed equalsA) e+c(B) 'er' +C(B)3e

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Solution

## The given integration is, ∫ x 2 e x 3 dx Assume, x 3 =t Differentiate with respect to x. 3 x 2 = dt dx dx= dt 3 x 2 Substitute the values in integration, we get, ∫ x 2 e x 3 dx = ∫ x 2 e t dt 3 x 2 = ∫ e t 3 dt = e t 3 +C Now, substitute the value of t in the above equation, we get, ∫ x 2 e x 3 dx = e x 3 3 +C Therefore, Option (A) is correct.

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