Question

$23gm$ of sodium of reaction with methyl alcohol gives:

• A. half mole of $H_2$
• B. one mole of $H_2$
• C. one mole of $O_2$
• D. $none$

Answer 1

Answer: (B)

one mole of $H_2$

$2C{H}_{3}OH+2Na\to 2C{H}_{3}ONa+H_2$

We see 2 moles of sodium react with methyl alcohol and produces 1 mole $H_2$ . Thus 28 gram sodium produces 1 mole hydrogen.