Question

23 gram of $N{O}_2$ contains same number of molecules as:

• A. 8 grams of oxygen
• B. 28 g of carbon monoxide
• C. 16 grams of $S{O}_2$
• D. 22 gram of $C{O}_2$

Answer 1

Answer: (D)

22 gram of $C{O}_2$

Applying the concept:
No. of molecule = $\frac{N_A}{molecularwt}\times givenwt$

No. of molecules in 23g of $N{O}_2$ = $\frac{23\times N_A}{46}$ = 0.5$N_A$

A) No. of molecules in 8g of $O_2$ = $\frac{8\times N_A}{32}$ = 0.25$N_A$

B) No. of molecules in 28g of CO = $\frac{28\times N_A}{28}$ =$N_A$

C) No. of molecules in 16g of $S{O}_2$ = $\frac{16\times N_A}{64}$ = 0.25$N_A$

D) No. of molecules in 22g of $C{O}_2$ = $\frac{22\times N_A}{44}$ =

0.5$N_A$

Therefore (D) is the correct answer.