23 students of a class are arranged in such a way that the front row consists of 15 girls and the second-row consists of 8 boys. The two corner positions of the second-row are reserved for the 2 tallest boys. In how many ways can the students be arranged?
2!*15!*6!
The number of ways in which this can be done is 2!*15!*6!.
15! is the no. of arrangements of the girls, 2! is the no. of arrangement s of the 2 tallest boys and 6! is the no. of arrangements of the remaining 6 boys.