Question

$23\times 51=?$. Evaluate using Urdhav Triyak :

• A. 1163
• B. 1173
• C. 1263
• D. 1273

Answer 1

The correct option is B 1173


2 3
5 1
___________
2x5 / 2x1 + 5x3 / 3x1
10 / 17 / 3
10 + 1 / 7 / 3 $\Rightarrow 1173$

1. Multiply the digits at one's place. Thus (3 x 1 = 3) and write it at the unit place of the product.
2. Cross multiply and add the products. Thus (2 x 1 + 5 x 3 = 17).Write it at ten's place.(Carry over 1)
3. Multiply the last digits (here the digits at ten's place). Thus (2 x 5 = 10). Add the carry over 1 to 10 = 11. Write it at hundred's place.