Question

${}_{92}^{238}U$ atom disintegrates to ${}_{84}^{214}Po$ with a half life of $4.5\times {10}^9$ years by emitting six alpha particle and n electrons. Here n is$?$

• A. $6$
• B. $4$
• C. $10$
• D. $7$

Answer 1

Answer: (B)

$4$

Six alpha particle mean total 12 neutron and 12 proton. So the atomic number will become 80, but with release of 4 electron the the atomic number will become 84. Its beta decay, neutron is converted to a proton and the process creates an electron.