24.A deutron and an alpha - particle with same kinetic energy enter perpendicular to uniform magnetic field . Then ratio of radii of their respective circular paths is a- root 2 : 1 b- 2: 1 c- 1 : 2 d- 1 : 1

Open in App

Solution

Suggest Corrections

Similar questions

Q. A proton, a deutron and an

α

-particle with same kinetic energy enter perpendicularly in a uniform magnetic field, then the ratio of radii of their circular paths is

A proton, a deuteron (nucleus of $1_{H}^{2})$ and an $α$ -particle with same kinetic energy enter a region of uniform
magnetic field moving at right angles to the field. The ratio of the radii of their circular path is

Q. A proton, a deutron and an

α

particle of same kinetic energy enter in a uniform magnetic field perpendicularly. The ratio of their circular path will be

A proton and an alpha particle enter the same magnetic field which is perpendicular to their velocity. If they have same kinetic energy then ratio of radii of their circular path is

Q. A proton and an

α

- particle (Helium nucleus) enters a uniform magnetic field with their direction of velocity perpendicular to the direction of magnetic field.

(i v)

If proton and

α

- particle enter the magnetic field, perpendicular to it with same kinetic energy, then the ratio of the radii of curvature of proton and

α

- particle will be

[

1 Mark

]

Join BYJU'S Learning Program