QUESTION 2.24

Based on solute - solvent interactions, arrange the below given in order of increasing solubility in n - octane and explain.
Cyclohexane, KCl, $C H_{3} O H$ , $C H_{3} C N$

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Solution

(i) Cyclohexane and n-octane both are non-polar.
So, they mix completely in all proportions.

(ii) KCl is an ionic compound, but n - octane is non-polar.
So, KCl does not dissolve in n-ocatne.

(iii) $C H_{3} O H$ and $C H_{3} C N$ both are polar but $C H_{3} C N$ is less polar than $C H_{3} O H$ . As the solvent is non-polar, $C H_{3} C N$ will dissolve more than $C H_{3} O H$ in n-octane.

Order of solubility is $K C l < C H_{3} O H < C H_{3} C N < c y c l o h e x a n e$ .

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