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Concentration Terms

24.Calculate ...

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24.Calculate the equivalent weight of KI in given reaction: CuSO4+KI->Cu2I2+K2SO4+I2

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Q. What will be the equivalent weight of

C u S O_{4}

in terms of its molecular weight m in the following reaction?

C u S O_{4} + 4 K I \to C u_{2} I_{2} + I_{2} + K_{2} S O_{4}

Q. In the reaction

2 C u S O_{4} + 4 K I \to C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}

, the equivalent weight of

C u S O_{4}

(M w = 159.5 g

m o l^{- 1})

Q. In the reaction,

2 C u S O_{4} + 4 K I ⟶ C u_{2} I_{2} + 2 K_{2} S O_{4} + I_{2}

, the ratio of equivalent mass of

C u S O_{4}

to its molar mass is :

Q. In an iodometric estimation, the following reactions occur

2 C u^{2 +} + 4 I^{-} \to C u_{2} I_{2} + I_{2}; I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

0.12 m o l e

C u S O_{4}

was added to excess of

K I

solution and the liberated iodine required

120 m L

of hypo. The molarity of hypo solution was:

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

100

0.02 M C u S O_{4} (a q)

10

0.02 M

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

0.1 M

hypo solution for its complete reduction.The amount of

I_{2}

liberated in the reaction of

10

0.02 M

solution with excess

K I

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